python编写一个xss漏洞扫描器扫描网页url是否存在xss漏洞代码

代码语言:python

所属分类:web系统

代码描述:python编写一个xss漏洞扫描器扫描网页url是否存在xss漏洞代码

代码标签: xss 漏洞 扫描器 扫描 网页 url

下面为部分代码预览,完整代码请点击下载或在bfwstudio webide中打开

#!/usr/local/python3/bin/python3
# -*- coding: utf-8 -*
import requests
from pprint import pprint
from bs4 import BeautifulSoup as bs
from urllib.parse import urljoin


def get_all_forms(url):
    """获取url网页中的所有form表单"""
    soup = bs(requests.get(url).content, "html.parser")
    return soup.find_all("form")


def get_form_details(form):
    """
   获取form表单的详细信息,如post method action等
    """
    details = {}
    # get the form action (target url)
    action = form.attrs.get("action").lower()
    # get the form method (POST, GET, etc.)
    method = form.attrs.get("method", "get").lower()
    # get all the input details such as type and name
    inputs = []
    for input_tag in form.find_all("input"):
        input_type = input_tag.attrs.get("type", "text")
        input_name = input_tag.attrs.get("name")
        inputs.append({"type": input_type, "name": input_name})
    # put everything to the resulting dictionary
    details["action"] = action
    details["method"] = method
    details["inputs"] = inputs
    return details


def submit_form(form_details, url, value):
    """
    模拟提交表单
    Params:
        form_details (list): a dictionary that contain form information
        url (str): the original URL that contain that form
        value (str): this will be replaced to all text and search inputs
    Returns the HTTP Response after form submission
    """
    # construct the full URL (if the url provided in action is relative)
    target_url = urljoin(url, form_details["action"])
    # get the inputs
    inputs = form_details["inputs".........完整代码请登录后点击上方下载按钮下载查看

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